x^(5/2)=1/32

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Solution for x^(5/2)=1/32 equation:


D( x )

x < 0

x < 0

x in <0:+oo)

x^(5/2) = 1/32 // - 1/32

x^(5/2)-(1/32) = 0

x^(5/2)-1/32 = 0

1*x^(5/2) = 1/32 // : 1

x^(5/2) = 1/32

x^(5/2) = 1/32 // ^ 2

x^5 = 1/1024 // ^ 1/5

x = 1/4

x = 1/4

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